Dioptra App Moon sighting vs Redshift 8 professional planetarium software prediction

The Dioptra App and the Redshift 8 planetarium software are promising tools which should have applications in doing experiments in the spherical earth vs flat earth controversy. Here’s some preliminary results testing these tools and a proposal for one way they could be used in a future experiment to test spherical vs flat earth models.

I remember getting the Redshift software for my Mac back in the mid 90s and successfully using it to predict and identify planets and stars and their positions in the night sky. There are quite a few brands of similar software on the market now, but without doing too much research I decided to go with the current premium version of Redshift now available for around $60.

So I took a sighting of the Moon with the Dioptra App on my Android Smart phone and then entered the same time and location parameters into Redshift for comparison.

Dioptra: Azimuth 102 deg magnetic & Altitude 38.4 deg

Redshift: Azimuth 114.9 deg true = 101.6 deg magnetic & Altitude 39.8 deg

This seems like pretty good agreement, but I will investigate further to determine if the results are within the experimental uncertainties expected for Dioptra and Redshift, or if there are any other explanations for the slight differences.

I plan to get a couple of friends, one over 900 miles north of me in Canada, and another almost 500 miles south of me in San Diego to take similar sightings of the Moon when high in the sky, and compare with my sightings, in order to determine if the data is consistent with the spherical earth model or a flat earth model. This should be a very simple and straightforward calculation to perform, taking into account the precise locations in terms of latitude and longitude for the sightings and also the precise times for the sightings.

I will report on those results once they are available, and I encourage others to do similar experiments and report on their results.

 

Flat earth geometry compared to actual San Jose CA 400 meter running track

How a flat earth 400 m running track would layout over actual San Jose CA Lynbrook High track

Here are two 400 meter track traces laid out over the Lynbrook High School track in San Jose, CA, one according to spherical earth surface geometry, and the other according to flat circular disk earth geometry, which is shifted slightly to the west (i.e. left) to make it easier to distinguish between the two for comparison purposes.

It is worth pointing out that there are two ways to compare spherical to flat geometry that should be distinguished to avoid confusion. Two blog posts ago where I first introduced walking a track and taking GPS data where I did this at Prospect High School, I showed how the actual GPS trace coincided accurately with the real map of the track and I will further note here that 5.58 km/12 = 465 m/lap is reasonably close to what would be expected for the 8th lane based on a quick web search for that information which gave 454 m/lap. And if you keep the trace the same but instead calculate how far that trace would have gone on a flat earth interpretation, you get almost 10% higher 6.01 km/12 = 501 m/lap. So to emphasize, this is keeping the trace the same and calculating the higher distance you would get with the flat earth geometry interpretation.

Instead in what I am illustrating in this blog post I am figuring out what the trace would need to be according to flat earth geometry in order to give the same distance as the actual track (spherical earth interpretation which is 400 m for lane 1). This is the reason why in this case, the flat earth trace shows up as smaller compared to the actual trace. So here we keep the distance travelled the same and get different traces for flat versus spherical, whereas in the previous case cited of 2 blog posts back of Prospect High School, the traces are kept the same so you then get different distances for flat versus spherical.

The Excel file with these traces is documented here.

SimSphFltLynbrookTrackLapVis      Excel file

SimSphFltLynbrookTrackLapVis      Excel file

This illustrates how the distortion between flat and spherical geometry although not nearly as extreme as that shown in the previous blog post for Santiago Chile, is nevertheless significant and obvious to the eye here at the northern latitude of San Jose, CA.

How 3 flat earth 400 m running tracks would layout over actual Santiago Chile Escuela PDI track

These are actual traces of what properly proportioned 400 m tracks laid out in Santiago Chile according to flat earth circular disk geometry would look like compared to an actual existing properly proportioned track there at Escuela PDI.

Three flat earth geometry tracings of properly proportioned 400 meter tracks overlaying actual 400 meter track in Santiago Chile, one tracing with long dimension running north south and two with long dimension running east west. The flat earth trace with the long dimension running north south exhibits the proportion similar to that of a cigar, whereas the two flat earth traces with long dimensions running east west exhibit the proportions of a pill box.

The Excel file with these traces is documented here.

ChileLeftRightShaftV2Vis      Excel file

ChileLeftRightShaftV2Vis      Excel file

This graphically illustrates the gross distortions in dimensions that occur in the southern lands when comparing imaginary flat earth geometry to real spherical earth geometry.

Running Tracks Worldwide Affirm Spherical Earth

Spherical Earth Affirming One Running Track At A Time

GPS+RunningTrack=FlatEarthDebunked

INTRODUCTION

In my previous blog post I mentioned looking at shorter trips and even walking routes that might give ample evidence to clearly affirm the spherical earth and debunk the flat earth.

And as I have tried a few different things, I have come upon a concept that will truly bring spherical earth affirming and flat earth debunking to the masses all over the world.

It turns out that no matter where you go throughout the world, wherever there is civilization, there are sports fields and running tracks, the tracks being nominally 400 meters around for one lap. It is true that there have been some different standards throughout the years, so tracks of differing dimensions will certainly be found. But anyone could easily measure for themselves the dimensions of their track for further verification if desired.

So no matter where most people live, they are most likely going to be able to find a nearby school with a track where they can go and do some walking (or running) around the track and do experiments with their GPS’s.

I have already done three different tracks at schools close to where I live. I will share the details of the one I just did yesterday.

PROSPECT HIGH TRACK WALK

I walked 12 laps in 1 hour 8 minutes 43 seconds. I stayed in the outermost lane the whole time, which in this case happened to be lane 8. I noted exactly where I started and after each lap would pause at that point for a few seconds just to mark that in the GPS data trace. As before, I used the tracking feature in GPS Essentials on my smartphone.

Once you finish the walk, you stop the tracking and then export the KML file. I then go to the website GPSVisualizer.com where I can upload the file and manipulate it in various ways, as I have explained in detail in previous posts. If you wish you can immediately have GPSVisualizer display the trace on a google map. I also convert it to a text file so I can import it into Excel where I do other calculations of my own, which again I have covered in detail in previous posts.

The beauty of using these running tracks is that they are pretty much standard throughout the world and wherever they are you can find them on google maps and verify that the traces of these tracks in terms of latitude and longitude make sense according to spherical earth surface geometry, but show major inconsistencies when trying to explain them according to flat earth circular disk surface geometry.

The inconsistencies become greater and greater the further south you go, so that in South America or Australia the inconsistencies are truly gross. Do you suppose that there may be some Olympic records that need to be adjusted according to flat earth theory? This is truly an important question to ponder. This is not unlike in an earlier blog post where I pointed out that the around the world flight non-stop without refueling was much more impressive and a greater world record according to flat earth theory.

So for my trip around the track 12 times I travelled 5.58 km at an average speed of 4.88 km/hr and these checked out with my own independent calculations in the Excel spreadsheet. For the flat earth surface geometry, the Excel spreadsheet showed that I travelled 6.01 km at an average speed of 5.25 km/hr in flat earth fiction land. The Excel spreadsheet also showed that the fictitious flat speed increased in a regular pulsating manner throughout the walk according to the regular changes in heading that going around a regular shaped track naturally produces.

As before I am sharing all my files through my Scribd account. You would at least need to register for a free Scribd account to be able to download the files, I believe.

20171210182010-38065-data      text file

text file

558488ProspectTrack8thLane      Excel file

Data in Excel file

558488ProspectTrack8thLaneSphFlt     Excel file

Spherical & Flat cases processed in one Excel file

I have also set up a special email address where anybody can email me GPS data files that they might like me to process for them. I have no idea how many might send me such files, so I cannot make any promises about processing all of them. Certainly those with some written explanation of what is included would rate higher in priority to process.

SphereAffirmer@att.net

WILL FLAT EARTH ADVOCATES INDEFINITELY CLAIM THEY HAVE NO FLAT EARTH MAP?

We simply cannot let the flat earth advocates continue to use their ruse of claiming they have no flat earth map to continue evading the clear deviations from reality of their theory. The problem is that different aspects of their theory together lead to conflicting conclusions. I covered this in a satirical manner in my earlier blog post on Tri-Location on the Flat Earth.

So let me just state the simplest part of their theory that should clearly establish a correspondence between coordinates on the spherical earth map versus their claimed flat earth map. Since they show the Sun completing a cycle in 1 day or 24 hours, the Sun would have to traverse 360 degrees of longitude in 24 hours. This would be the same whether you have a spherical earth or a flat circular disk shaped earth. So if you know the longitude of a city on the spherical earth its longitude should be exactly the same on the flat earth map. Similar arguments can be made that latitude should also be equivalent if the equator and tropics of Capricorn and Cancer are interpreted equivalently between spherical and flat models, as surely they must be or the flat earth theory makes absolutely no sense at all.

So if you were to go to a southern hemisphere place in Chile or Australia and layout a running track according to flat earth geometry of latitude and longitude its shape will be grossly different than the actual running track laid out according to real measurements and also in precise agreement with spherical earth surface geometry of latitude and longitude. I plan to show this graphically in a future post.

 

Flat Earth If It Doesn’t Fit It Must Be Shlt

INTRODUCTION

This presents more data and its processing and analysis just like the previous blog post. All the explanatory details do not need to be repeated here. If you need to, refer back to the previous post. As before, all files are shared freely on my Scribd account, so people can see and check and analyze my work, and use these files to do their own experiments for themselves no matter where they are in the world.

For review I just want to summarize the basic concept upon which these types of experiments are based.

You travel a route and track it with GPS and independent odometer and speedometer, and maintain constant speeds as much as you can throughout the trip and note this information also. Afterwards you process the latitude longitude data versus time according to spherical earth surface geometry and flat circular disk earth geometry and compare the results. Invariably what you will find is that the spherical geometry interpretation reconciles all the data with itself. The flat geometry interpretation leads to significant contradictions.

It is really up to flat earth advocates to explain how the data should be interpreted in order to make it conform in all ways to flat earth geometry and theory and at the same time to reality. I claim that to make this fit flat earth theory is an impossibility. The pizza pie is really in their pizza oven now.

Now the way that I am interpreting the data according to flat circular disk earth geometry is to take the latitude longitude data and interpret it with the azimuthal equidistant map as if it were a flat earth map. Now I have tried interpreting it in two other possible ways consistent with different aspects of flat earth theory. Both of these ways also lead to significant contradictions.

One way is shifting all of the latitude data points up by the same amount to bring the west east gradient in terms of miles traveled per degree of longitude the same on flat circular disk earth geometry as it is on the spherical earth where the data was actually taken. This ends up fitting the speedometer and odometer data pretty well, but obviously the location is way off, as it shifts my San Jose data north around 500 miles to approximately Sisters Oregon.

Could flat earth advocates actually have an uncertainty of locating a place on the flat earth map of as much as 500 miles? If their “map” which they claim not to really have yet, has this much uncertainty, then what business do they have using any so called “flat earth map” to justify all of their many claims that the earth is flat, like the way that the Sun and Moon circle around it, and the way that airline flights make more sense (they claim) on the flat earth map than on the spherical earth map?

And then the other way I have tried to make the data fit flat earth circular disk geometry is to essentially flatten the spherical data and then plop it somewhere on the flat earth map. The spherical data itself is close to being flat just by its nature of being a route of not much overall distance on the earth, but mathematically it is kind of like me taking that route that is already pretty close to flat and putting it on an ironing board and ironing it flat so I can then easily plop it onto any flat earth map. Here again, we would need the flat earth advocates to tell us where to plop it. So I choose making the starting point of latitude and longitude the same on the flat as on the spherical. When I do this, there is quite a bit of agreement, but the route ends up not coinciding with the actual route of the trip. Again, it just does not fit. At this point I am holding off on presenting this additional information in detail, until I can find a way to present it in as simple and understandable way as possible. Also, I want to give flat earth advocates a chance to struggle with trying to make their flat earth model fit the real world data.

How long can flat earth advocates keep hiding underneath their undefined flat earth map?

Eventually many will have no choice but to exclaim, “Look! The Flat Earth Emperor is wearing no map!”

SO NOW ON TO PRESENTING THE NEW DATA

Here I want to illustrate how a shorter trip can provide good data for this type of experiment and analysis. After this perhaps I will try an even shorter trip by car around just residential streets. If that ends up working OK, then the next step might be to see if the experiment can be done by walking a route around the neighborhood.

The same file naming scheme as before is still used. The previous blog explained the rationale behind this. In this case in the Excel files the data extends down to row 1642.

For this trip I was able to hold a constant speed with cruise control for almost the entire distance on the freeway. There was really just one place where I had to slow down briefly for some night time construction work. As before, the constant speed held shows up very clearly in the data processed according to spherical earth geometry, whereas when the data is processed according to flat earth geometry the long intervals of constant speed deviate markedly from being constant. Here’s the results.

Freeway Circle Around Home in San Jose

35.2 km (21.9 miles) by odometer

Duration by watch 0:32

Duration Start to Stop GPS 0:32:20

35.1 km 65.1 km/h ave speed 97.2 km/h top speed by GPS

35.054 km 65.015 km/h ave speed confirmed by calculations in Sph Excel spreadsheet

Speed versus Time plot for spherical model shows clear agreement with speedometer data

Speed versus Time plot for flat model shows large deviations from speedometer data

38.2 km 70.9 km/h ave speed by calculations in Flt Excel spreadsheet Inconsistent with odometer data

Spherical Earth model: Affirmed

Flat Earth model: Large deviations from reality

Speed versus Time according to Flat theory

Speed versus Time according to Flat theory

Speed versus Time according to Spherical theory

Speed versus Time according to Spherical theory

Speed versus Time according to Spherical and Flat theory all on the same graph.

Speed versus Time according to Spherical and Flat theory all on the same graph

I have made these files available to the public through my Scribd account.

20171130214830-38065-data    Text file

20171130214830-38065-data     Text file

351651FreewayCircleAroundHome           Excel file

351651FreewayCircleAroundHome           Excel file

351651FreewayCircleAroundHomeFlt        Excel file

351651FreewayCircleAroundHomeFlt        Excel file

351651FreewayCircleAroundHomeSph       Excel file

351651FreewayCircleAroundHomeSph       Excel file

Anybody should be able to see the files by just going to the links. The graphs of Speed versus Time for both the spherical and flat cases should be able to be seen this way in addition to the links earlier in this post. To download the files you need a Scribd account, and a regular account should be free to set up.

I was not able to make the KML file Track-171130-210519 available through Scribd because it is not a supported file type.

I encourage people all over the world to take their own data and process it in this manner and report their results. Let me know if you have any questions. Comments are welcome. Thank you.

 

GPS + Odometer + Speedometer + Cruise Control = Spherical Earth Affirmed (San Jose to Berkeley)

GPS+Odometer+Speedometer+CruiseControl=SphericalEarthAffirmed(SanJoseToBerkeley)

INTRODUCTION

I recently got a very helpful suggestion from a person in Santiago, Chile, that expressing my work in metric units would be helpful to the international community, so this motivated me to travel metrically on a trip yesterday, as much as I was able, and to report the experimental results metrically as well.

In a nutshell, you track a car trip with your GPS and use cruise control to maintain intervals of constant speed as much as you can during the trip, noting the constant speeds you maintained as well as where on the trip you were able to do so. Once you get the GPS data you can analyze it and show that a spherical earth surface geometry interpretation of the data accurately gives the regions of constant speed and the overall trip distance in agreement with the car’s odometer and speedometer. On the other hand when you interpret the data according to flat circular disk geometry the intervals of constant speed do not show up as constant at all and the overall trip distance is much in error from the distance measured by the car’s odometer. I can already hear flat earth advocates saying something like the GPS data comes out right because it is based on spherical geometry, and indeed I agree that it is so based, but the car’s odometer and speedometer are independent of what theory of the earth’s surface you hold. The car should give accurate speeds and distances traveled whether you are on a flat earth or a spherical earth, or any other shape for that matter. The fact that the GPS data agrees with the independent data from the car’s odometer and speedometer is strong evidence that the spherical earth model is correct. The fact that the GPS data when interpreted according to flat circular disk geometry disagrees profoundly with the independent data from the car’s odometer and speedometer is strong evidence that the flat earth model is incorrect. I challenge all flat earth advocates and researchers to find a way to interpret the trip GPS data so as to show that it conforms to flat earth theory and also agrees with the independent data of the car’s odometer and speedometer.

The beauty of this experiment is that whenever someone does it they are going to get unique results that cannot possibly be predicted or planned for in advance. Where and at what speeds you are able to hold steady speeds with cruise control will vary with the road and traffic conditions. The path of the trip used will also impact the results in a unique way.

This type of experiment can easily be performed for a vast variety of trips all over the world and the data easily analyzed. I am going to share exactly how this can be done by showing how I did it for a trip from San Jose to Berkeley CA yesterday. All details are presented and the Excel files are made available to anyone through my Scribd account so they can see how it was done and use the spreadsheets to process the data from their own trips as well.

DETAILS FOR TRIP FROM SAN JOSE TO BERKELEY

I used the GPS in my smartphone, a Samsung Galaxy S4. I used the App GPS Essentials, where at the start of your trip you start tracking, and when you arrive at your destination you stop tracking. The trip file can then be exported as a KML file. From there you can process the data in various ways. I like to use the website GPSVisualizer.com for some things and Excel spreadsheet for many other things.

Car speedometer and odometer

It was easy to push a button to get my speedometer to read in km/h instead of mph, so that way I could easily see what my speed was in km/h during the trip. I was not sure how or if I could get the odometer to read in km, so I took the readings in miles and converted to km.

Trip from San Jose to Berkeley

91.1 km (56.6 miles) by odometer

Duration by my watch 1:10

Duration Start to Stop GPS 1:09:28

90.6 km 78.3 km/h ave speed 131 km/h top speed reported directly by GPS

From my smartphone I exported the trip KML file via email to my PC. The KML filename was Track-171126-105544. I then went to the website GPSVisualizer.com, where I uploaded the KML file and choose output format plain text table. I then clicked the link to download this text file back to my PC. I accepted the default filename 20171126171339-38065-data. I then opened the Excel spreadsheet application. My version happens to be from 2010. From within the Excel application, find the text file and open it. Either select to look at All Files or just Text Files to make sure you can see the correct text file to open. Once you open it, the Text Import Wizard comes up. The default settings are fine, so just click on Next, Next, and then Finish. At this point I like to do a Save As on the file, and save it as an Excel Workbook file, and give it a name that is more meaningful to me. So I gave it the name 906783SanJoseToBerkeley. I got the 906 from 90.6 km for the trip and 783 from 78.3 ave speed for the trip in km/h and added SanJoseToBerkeley to further help me identify this data. I will use this name with additional things added to it as more files are produced based on processing this data. I do not intend to make any further modifications to the Excel Workbook file 906783SanJoseToBerkeley so this can be kept as a record of this stage of the data processing procedure that could easily be returned to as needed. So then I will again do a Save As to the file and give it the name 906783SanJoseToBerkeleySph. This will be the file where some modifications will be made so it will do calculations according to spherical earth geometry. One other change I like to make at this point is to rename the data tab. So go to the lower left and right click on the data tab, that currently has the really long name that came from the GPSVisualizer when it created the text file from the KML file, and select rename. I like to rename it 906783-data. Once you do this be sure to save the file again. And then do another Save As and save it with the name 906783SanJoseToBerkeleyFlt. This will be the file where some modifications will be made so it will do calculations according to flat circular disk shaped earth geometry.

So let’s start by working on the 906783SanJoseToBerkeleyFlt file. If you have followed the directions exactly as above that file should already be open. If not, open it now. Also open the Excel file FltGeomMetricUnitsTemplate. This is the file where we are going to copy the section with the equations for calculation and paste them into file 906783SanJoseToBerkeleyFlt.

In the 906783SanJoseToBerkeleyFlt file select across from Column E to Column J, so that Columns E, F, G, H, I, and J are all selected. Be sure to select across the column headings so that the entire columns will end up being selected. Then Right-Click anywhere inside the selection and choose Insert. This then creates 6 empty columns from E to J, and moves the other stuff to the right so nothing is lost. In these 6 columns is where we are going to do some calculations on the data. So we are now going to get the equations from the FltGeomMetricUnitsTemplate file and copy and then paste into the new spreadsheet. So from FltGeomMetricUnitsTemplate select from E1 upper left to J12 lower right so that a rectangle of 12 cells down and 6 cells across are selected. Then Copy (Ctrl-C). Then go to the 906783SanJoseToBerkeleyFlt spreadsheet file and select cell E1 to define the upper left of where to Paste. Then Paste (Ctrl-V). At this point the equations need to be filled down to the extent of the data. Select cell E12 which defines the upper left. Scroll down to the very bottom of the data, in this case row 3416. Shift-Click on cell J3416. This will result in all cells bounded by E12 on the upper left to J3416 on the lower right to be selected. Then do a Fill Down (Ctrl-D). This then results in the equations being pasted all the way down so we get the calculations done that we wanted for the entire extent of the data. Two values can be read off of the spreadsheet at this point. If you go to cell G3416 the total distance of the trip according to flat earth interpretation is 96.2 km and to cell I3416 the average speed is 83.1 km/h also according to flat earth theory. Next we will create a plot of speed versus time. Column J is speed smoothed over several data points and is what I will use because it minimizes the natural scatter in the data for a better looking plot. If you want to use the point to point speed just use column H for speed instead. So select from cell B12 to B3416. The way I like to do this is first select cell B12, then scroll all the way down and shift-click on cell B3416. Next we want to add to the selection cells J12 to J3416. The way I like to do this is first Ctrl-click on cell J12 and then scroll down and shift-click on cell J3416. Now that we have selected two separate columns, one defined by cells B12 to B3416, and the other defined by cells J12 to J3416, we can create a plot of this speed versus time data. So go to Insert, select Scatter, and then Scatter with straight lines is the one I like. This puts the plot in front of the spreadsheet table. I like to make it separate with its own tab. So right click in the right area of the plot and chose Move. Then click the button and accept the default name of Chart1 or give it your own name. I like to call it SpeedVsTimeSm, for speed versus time smoothed. This then is the speed versus time plot based on the flat earth interpretation of the data. This will eventually be compared with the equivalent plot based on the spherical earth interpretation of the data. What we will find is that the intervals where the speed was held constant with cruise control show up clearly and distinctly constant on the spherical earth interpretation, but with much variability on the flat earth interpretation.

So basically to get the equivalent calculations for the spherical earth surface model, repeat everything above, but instead using SphGeomMetricUnitsTemplate and working on file 906783SanJoseToBerkeleySph.

Once you do this you will get the results that I have summarized below.

Trip from San Jose to Berkeley

91.1 km (56.6 miles) by odometer

Duration by watch 1:10

Duration Start to Stop GPS 1:09:28

90.6 km 78.3 km/h ave speed 131 km/h top speed by GPS

90.67 km 78.32 km/h ave speed confirmed by calculations in Sph Excel spreadsheet

Speed versus Time plot for spherical model shows clear agreement with speedometer data

Speed versus Time plot for flat model shows large deviations from speedometer data

96.2 km 83.1 km/h ave speed by calculations in Flt Excel spreadsheet Inconsistent with odometer data

Spherical Earth model: Affirmed

Flat Earth model: Large deviations from reality

If I am able to display the Speed versus Time graphs I will show them here. If not they can be seen at the Scribd links.

Speed versus Time according to Flat theory

Speed versus Time according to Flat theory

Speed versus Time according to Spherical theory

Speed versus Time according to Spherical theory

I have made these files available to the public through my Scribd account.

20171126171339-38065-data    Text file

20171126171339-38065-data    Text file

906783SanJoseToBerkeley           Excel file

906783SanJoseToBerkeley           Excel file

906783SanJoseToBerkeleyFlt        Excel file

906783SanJoseToBerkeleyFlt        Excel file

906783SanJoseToBerkeleySph       Excel file

906783SanJoseToBerkeleySph       Excel file

FltGeomMetricUnitsTemplate         Excel file

FltGeomMetricUnitsTemplate         Excel file

SphGeomMetricUnitsTemplate         Excel file

SphGeomMetricUnitsTemplate        Excel file

Anybody should be able to see the files by just going to the links. The graphs of Speed versus Time for both the spherical and flat cases should be able to be seen this way. To download the files you need a Scribd account, and a regular account should be free to set up.

I was not able to make the KML file Track-171126-105544 available through Scribd because it is not a supported file type.

I encourage people all over the world to take their own data and process it in this manner and report their results. Let me know if you have any questions. Comments are welcome. Thank you.

Flat Earth Tri-Location – Former NASA engineer presents rigorous derivation of previously reported discovery

Warning: The following is satire. It could be viewed as blasphemous to some religious zealots (as I once was). Read at your own risk.  If you are easily offended by satire, and not at all able to make fun of yourselves and your fellow earthians, whether flat or spherical or undeclared, as well as your creator God if you so believe, and religion, especially of the narrow-minded type, then you should stop reading right now.  Get thee quickly far from here.  You have been warned.  Future complaints from those who proceed to read without heed and are offended by the satire will be ignored.

INTRODUCTION

As promised in the previous announcement of this discovery in flat earth theory made on October 17, 2017, the detailed derivation is given below of tri-location on the flat earth. It is shown that while one is present on the flat earth, they are actually simultaneously present in three distinct places, dubbed primary, secondary, and tertiary, hence tri-located on the flat earth.  This derivation is presented to all flat earth researchers and other more mainstream scientists and others for open peer review.

LONGITUDE

First consider longitude. Whether you are on the spherical earth map or the flat earth map if you travel west to east (or vice versa) your position will change in longitude.  In both cases if you travel a total of 360 degrees of longitude you will end up right back where you started.  On the spherical earth the earth rotates once every 24 hours.  If you used a reference frame of a stationary (non-rotating) spherical earth the sun would appear to be circling around the earth once every day traversing a total of 360 degrees of the earth’s longitude each day.  On the flat earth the sun is considered to be circling above the stationary flat earth and around the north pole so that in one day it traverses a total of 360 degrees of the earth’s longitude.  So longitude is consistent between the spherical earth and flat earth models.  If you define zero longitude as the prime meridian through the Royal Observatory at Greenwich London for both spherical and flat models, longitude would have to be perfectly equivalent between both models.  That means that if you are at a certain longitude on the spherical earth model, you would have to be at the same longitude on the flat earth model.

LATITUDE

Now consider latitude. Whether you are on the spherical earth map or the flat earth map if you travel south to north (or vice versa) your position will change in latitude.  In both cases if you start at any point on the equator and travel north a total of 90 degrees of latitude you will end up at the north pole.  The distance you will have traveled from equator to the north pole will have been the same whether on the spherical model or the flat model.  Latitude is defined as zero at the equator and positive as you go north.  Latitude is defined as negative as you go south from the equator.  So on the spherical model if you start at the equator and travel south to -90 degrees latitude you will end up at the south pole.  On the flat model if you start anywhere on the equator and travel south to -90 degrees latitude, instead of ending up at a point you end up on the “polar” ring.  But the distance traveled from equator to south pole on the spherical model will be the same as the distance traveled from the equator to the “polar” ring on the flat model.  And that distance is also the same as the distance from the north pole to the equator (same whether sphere or flat as earlier established).  It is clear from the above that latitudes are equivalent whether on a spherical or flat model.  Therefore if you are at a certain latitude on the spherical earth model, you must also be at the same latitude on the flat earth model.

PRIMARY LOCATION

So based on the above two paragraphs, when you are at a certain latitude and longitude according to the spherical earth map, you are actually at the same latitude and longitude on the flat earth. So when you realize that you are on the Flat Earth, this is the primary place where you are, at the same latitude and longitude as you would be if you were on the imaginary spherical earth.  But beyond this, is where it really starts to get interesting and exciting.

SECONDARY LOCATION

This is where it really helps to take some of your own measurements right where you live to make this as real to you as possible. For me, I live in San Jose, CA, so I used my car and its odometer to measure the distance between two defined points of longitude on a street that runs east-west, as well as between two defined points of latitude on a street that runs north-south.  From this data you can calculate the south to north gradient in terms of miles traveled per degree of latitude, as well as the west to east gradient in terms of miles traveled per degree of longitude. For the two gradients I got 69.1 miles traveled per degree of latitude, and 55 miles traveled per degree of longitude.  My location in San Jose is approximately 37.3 degrees latitude.

The south to north gradient is as expected and would be the same whether on a spherical or flat earth model.  The west to east gradient however needs to be factored into the correct equation for a flat circular disk in order to determine the latitude at which this gradient would occur.  That equation is gradient = 55 = (((90-deg lat)/90)*3959*3.14159^2)/360 and solving for latitude gives 44.4 degrees.  This means that while I am at 37.3 deg lat in San Jose on the Flat Earth as my primary location, I am also at 44.4 deg lat on the Flat Earth as my secondary location, which is just a few miles from Sisters Oregon.  As remarkable as this is, to realize that on the flat earth I am actually at two distinct places at the same time, it gets even more remarkable as we apply more principles of flat earth theory to the problem.

TERTIARY LOCATION

Back on the equinox of September 23, 2017 I took some of my own data where I live and found it to be consistent with what one would expect based on looking up the various parameters on the web.  Although I did not travel personally to the equator, I am relying on generally accepted parameters available on how one would experience the equinox there.  Based on this, and the flat earth assumption, I was able to determine that the sun was 5322 miles above the surface of the flat earth at the equator on the equinox.  Based on where I saw the sun in San Jose on the equinox, and the flat earth assumption, I was able to determine that I am 4054 miles north of the equator where I am in San Jose, CA, which would put me at 4054/69.1 = 58.7 deg latitude. Incredibly then, this puts me up in the northern part of British Columbia Canada, a few miles from Fort Nelson BC.  So this would be my tertiary location.

So now I have established that according to flat earth theory, when I am present in San Jose, CA on the flat earth as my primary location, I am actually simultaneously present in two other distinct places on the flat earth, at the same longitude, but at two distinct places further north in latitude, one placing me in Oregon and the other placing me in Canada.

ADVANTAGES OF FLAT EARTH SCIENCE OVER CONVENTIONAL SCIENCE

Within conventional physics, science, and mathematics, when different lines of reasoning and logic lead to different conclusions, called by those in the discipline contradictions, theories are often considered to be refuted.  But within flat earth science, also known by some as Biblically Based Science (BBS or Double B S), these apparent contradictions of the theory are actually viewed as further confirmation of the theory.  This is what is so beautiful and elegant about flat earth science, the more that it is seemingly refuted by conventional scientists and others, the more it is actually established as the absolute truth from God and His word the Bible, which cannot lie.  Satan is so clever to concoct so many contradictions to deceive us, but we know his game, as God’s word the Bible tells us, he is the father of lies.  The more Satan lies, the stronger our faith in the immovable flat earth becomes, so that the truth of the flat earth is irrefutable.

WHAT PEOPLE ARE SAYING

Many flat earth advocates and believers, having heard of these discoveries for the first time, are saying that they always felt like they were in multiple places at the same time, and now they are comforted to know that they were not crazy after all, that Biblical science confirms what they always knew in their hearts to be true.

LOOKING TO THE FUTURE

Future possibilities and ramifications of this research are far reaching and possibly limitless.  That tri-location has been proven on the flat earth, multi-location is not ruled out. As further advances are made in flat earth theory, the limit may even be beyond the firmament, or even beyond the firmament of firmaments.

Comments, feedback, questions, further insights are sought from fellow flat earth researchers, establishment scientists, and others, as a period of peer review is conducted.  After a period of peer review extending until the end of calendar year 2017, a report will be made on the results of the peer review, and its ramifications for the future of flat earth research in the twenty-first century and the ages to come.

Where on earth on The Flat Earth will the Flat Earth International Conference 2017 be held?

I pose this question to all within the current Flat Earth Theory advocacy movement, especially those who will be presenting at and attending the upcoming Flat Earth International Conference to be held November 9-10, 2017 in Raleigh, North Carolina.  I have already posed this same question to three of the speakers to be at the conference, in private communications, Rob Skiba and Mark Sargent (myself having been a purchaser and reader of their books), and also, Bob Knodel, but so far, have gotten no responses.

Can you inform the World Community of the coordinates of latitude and longitude for Raleigh, NC on the flat earth (in particular 201 Harrison Oaks Blvd, Cary, NC 27513), the location of the upcoming Flat Earth International Conference?  It would seem very odd indeed if flat earth advocates could not even tell the world where on the flat earth they are holding their flat earth conference.  I realize that flat earth theory is quite primitive at this point, but could you at least determine where on the flat earth map Raleigh, NC is within a 100 mile radius?  This seems like a very legitimate and fair question.

The coordinates on the spherical earth map for 201 Harrison Oaks Blvd, Cary, NC are 35.833, -78.772.

The World Community eagerly awaits The Flat Earth Movement’s answer to this very simple and important question.

Former NASA engineer makes major Flat Earth Theory discovery today October 17, 2017

It was discovered today by T. Mark Hightower, formerly an engineer with NASA but now retired and actively engaged in flat earth theory research, that current flat earth theory implies that while one is present in one place on the flat earth they are actually at the same time also in two other far away distinct locations on the flat earth.  (It may alternatively be possible that no one is actually present anywhere on the flat earth, but flat earth researchers consider this the null case where further study is not merited.)  The ramifications of this discovery are far reaching for the fledgling resurgence of flat earth research in the recent past as many were hoping that flat earth theory would be a tremendous simplification of our understanding of God’s fish bowl in which we live, but now it appears that flat earth theory may be just as complex, enigmatic, and paradoxical, as Einstein’s theories of relativity, quantum mechanics, string theory, and multiverse theory, where our cozy fishbowl with the ceiling of a planetarium was erroneously viewed as being the result of a big bang billions of years ago resulting in an expansive and seemingly infinite multidimensional space time continuum  containing countless galaxies, stars, black holes, planets, moons, asteroids, hemorrhoids, comets, explosive diarrhea, and aliens.  Practical applications of these new discoveries are firmaments away, but some day it is hoped that the average Flat Earthian will be able to transport him or herself to other places within the flat earth fishbowl instantly and at will, thereby saving tremendous amounts of energy, and also making it unnecessary for NASA to continue faking the launching of satellites and other spacecraft, saving even more money and energy and improving NASA’s public image on Youtube, Facebook, and Google, and also making it much less likely that it will be necessary to target NASA employees in a future false flag incident possibly made to appear as if it were carried out by a lone nut Flat Earthian.  Rigorous documentation of this discovery will be given in the near future (perhaps in a week or two) for peer review by fellow flat earth researchers, as well as conventional scientists and others.

Answering questions on vacuum, space, rockets, and space travel

On about September 21, 2017 I received via email some questions/comments related to vacuum and how rockets and spacecraft are able to operate in space.  I replied within about 1 day and my responses are presented below slightly edited.

QUESTIONS/COMMENTS AS PRESENTED

How can anything be propagated through space if it is a vacuum, nothing?

If space is a vacuum then what does the rocket push off of?

How does the rocket maintain its heading and not spin out of control if there is no air to stabilize off of?

Space travel believers will say that they use special propellant that when ejected out of the thruster nozzle has an equal and opposite reaction.

If that’s the case then wouldn’t the thrusters on let’s say the space shuttle when maneuvering to the ISS have to eject the special propellant faster than 17,500MPH which is the speed they are traveling?

All tests show that rockets don’t work in a vacuum.

T MARK HIGHTOWER’S RESPONSE

I am going to do the best I can to answer these questions as quickly as possible off the top of my head without consulting any sources of information beyond what I currently know.  These are all good questions and certainly more could be learned by studying these things more.

ON VACUUM

First regarding the question of vacuum, I think that even in space there is not a complete vacuum in the sense that you could find a cubic mile of space that does not contain at least one atom or atomic nuclei.

But even if you could imagine a cubic mile of space without even one atom in it, I believe that other physical phenomena could take place in this space, such as the transmission of light or other electromagnetic waves, and other things possibly (I would have to research this more).

Even if you could have completely empty space, it becomes kind of a philosophical question of what is “nothing.”  I think the view of physics is that even if you could have completely empty space, that is not nothing, but instead a part of reality, known as the space time continuum in physics.  I think this view that even empty space would not be nothing goes back to early philosophers even before Christ.  I would have to double check on this.

I know we have plenty of examples here on earth of physical phenomena taking place in a high vacuum, but we really cannot create a perfect and complete vacuum.

So before we had transistors, we had vacuum tubes.  These accomplished the same sort of electrical tasks that eventually became possible to do with transistors.  When multiple transistors integrated into an electrical circuit were eventually created on a silicon chip, we got computers and relatively shortly thereafter we got computers that ordinary people could buy and use.  But realize that there were digital computers even before transistors, and these computers used vacuum tubes.

But of course, the more common use of vacuum tubes initially was in radio and then eventually television.  So there is a lot going on within the vacuum of a vacuum tube, such as the flow of electrons in the vacuum, and I am remembering how vacuum tubes need a source of heat to operate, and that is done with the filament, which is basically like a separate electrical circuit within the vacuum tube that functions just like a conventional incandescent light bulb.  Also, the screens of the original televisions were cathode ray tubes which were themselves giant vacuum tubes where a fast moving electron beam is used to create the television picture.

Now moving on to the other space questions.  I will paste the questions/comments posed and intersperse my answers/comments.

Question: If space is a vacuum then what does the rocket push off of?

Answer: It pushes off from the mass of propellant reaction products that it expels at high velocity.  I answered this more completely in a separate blog post dated September 20, 2017.

Question: How does the rocket maintain its heading and not spin out of control if there is no air to stabilize off of?

Answer: A physical solid object in space would remain in motion unless acted upon by an external force.  If we were to imagine that it were far enough out in space such that there were no significant gravitational forces acting upon it, then it would continue moving in a straight line for example.  I am using moving in a straight line, because if I said it was at rest, it would raise the question of what is it at rest with respect to, so linear motion is easier to imagine for this thought experiment.  This would be conservation of linear momentum.  The center of mass of the object would continue to move in a straight line.  But if the object had a spin or rotation to it, that spin would also continue indefinitely, unless acted upon by a force to change the rotation.  Just to complicate the example a little for illustration, let’s say it was a spacecraft traveling with a couple of astronauts in it, and the spacecraft was of a long cylindrical shape with one astronaut at one end and the other at the other end, and the spacecraft was tumbling (spinning) end over end.  If the astronauts were to move from the ends to the middle of the spacecraft the rate of the spacecraft’s tumbling would increase.  This would be due to conservation of angular momentum.  By the way, an example of conservation of angular momentum that most people on earth are familiar with is when an ice skater gets to spinning with their arms extended outwards and perhaps even a leg extending outward, and then draws their arms inward as well as their leg, and then they end up spinning noticeably faster.

Question: Space travel believers will say that they use special propellant that when ejected out of the thruster nozzle has an equal and opposite reaction.

Answer: I would have to research this for details, but I can say this.  Once you are in space, to make changes or corrections in either linear motion or spinning motion you are going to need more than one thruster pointed in different directions in order to achieve any change that you might want.  Maybe it could be done with just one thruster if you had the ability to change the direction that the thruster points from the spacecraft.  But also, for in space use, the corrections you make are usually going to be relatively small, so you want your thruster to be easy to turn on and off.  So you wouldn’t want to be burning rocket fuel and oxygen for example.  This is where your special propellants come in.  For a propellant to work all it needs to be able to do is expel a mass at a certain velocity, the higher the better, because then you get more effect for the mass that you use.

Question: If that’s the case then wouldn’t the thrusters on let’s say the space shuttle when maneuvering to the ISS have to eject the special propellant faster than 17,500MPH which is the speed they are traveling?

Answer: The unreacted unejected propellant is already going at the same speed as the spacecraft before it is ejected.  To cause a change in the motion of the spacecraft it only has to be ejected at some velocity with respect to the velocity of the spacecraft.  A thorough discussion follows.

Presumably in this example the spacecraft is orbiting the earth in a stable orbit at whatever distance from the earth that would be necessary for orbiting at 17,500 mph.  This could easily be calculated but I am not going to do that now.  I just know from having heard these orbital speeds mentioned before that this would be at a distance from the earth where you would have a very high vacuum, meaning essentially no “air” drag on the vehicle.  This would mean that the spacecraft would keep moving in this orbit unless acted upon by an external force.

The reason it is not moving in a straight line is that gravity is continually exerting a force upon it in a direction perpendicular to its velocity.  This is known as centripetal force and it causes the spacecraft to be continually curving toward the earth.  But it is going fast enough that the curving is the right amount to keep the spacecraft circling or orbiting the earth.

If you wanted to cause the spacecraft to re-enter the atmosphere, all you would need to do is fire a thruster in the opposite direction to the velocity of the spacecraft.  Note that the propellant used would already be travelling at the speed of the spacecraft before it is reacted and released, so it is ejected at high velocity with respect to the spacecraft’s velocity.  In so doing, if it is fired long enough to decrease the velocity enough, and this could all be calculated ahead of time based on the performance characteristics of the thrusters, the slower speed will result in the force of gravity causing it to curve more than the curve required for the orbit, so the spacecraft will start to travel to lower altitudes and eventually start entering the atmosphere.  I have never felt the need to look into the numerical aspects of all of this, but it might be interesting to gather all of this information to see if it all makes sense.  But I suppose, if it is all fake, they could have just made it all calculate out correctly to deceive us all.

MORE ELABORATION ON PHYSICS

Just a little note about how physics works for the equation F=ma in order to help better understand what centripetal force is.  (I am reflecting upon when I first learned about this equation, taking physics for the first time in high school 44 years ago, where I learned how this equation explains why car accidents can kill you, but that’s another story.)  In reality this equation is a vector equation.  A vector has both magnitude and direction.  F is the force vector with both its magnitude and direction.  a is the acceleration vector also with both magnitude and direction.  Acceleration is also by definition the time derivation of the velocity vector.  So in words, F(magnitude&direction) = mass x a(magnitude & direction) or

F(magnitude&direction) = mass x (change in v/change in t)

Where v is the velocity vector also with magnitude and direction.

So if you were in a drag racer, and you got the green light, and you take off, you would feel yourself being pushed from behind by the back of the seat as the car accelerates in a straight line with you in it.  Your velocity would be changing in magnitude (increasing) while its direction stays the same, straight ahead.

Now if you were traveling in a car at a constant speed and in a straight line, but then you put the car into a turn of a certain radius but at constant speed, you would feel the side of the car pushing against you in the direction that the car is turning.  In this case you are experiencing a constant acceleration, that is, a change in the velocity vector with respect to time, but the velocity vector is changing in direction but not speed or magnitude.  So in this turn the centripetal force is the force being exerted by the ground on the tires of the car perpendicular to its forward motion in order to cause it to turn (with you inside), which is a constant acceleration maneuver.  To make it a little more personal for you in the car, the side of the car is pushing against you causing you to turn, a centripetal force causing the centripetal acceleration of you.

Most people are familiar with the term centrifugal force.  If you are sitting in the turning car, from your point of view as being in the car, known in physics as a rotating reference frame point of view, you feel a force throwing you to the outside of the car, that is indistinguishable from a gravity force from your point of view from inside the car.  This reminds me of the space station in 2001 A Space Odyssey, where it is spinning so as to create an artificial gravity, so the person is able to run around it as if they were running on a surface with a gravitational attraction.

Comment: All tests show that rockets don’t work in a vacuum.

Answer: I would like to review these tests so I can comment upon them.